## Algebra 1: Common Core (15th Edition)

$\frac{2x^{2}+17x-45}{(x-5)(x+4)}$
Given : $\frac{2x}{x-5} + \frac{9}{x+4}=\frac{2x(x+4)+9(x-5)}{(x-5)(x+4)}$ (Finding the least common denominator) This becomes : $\frac{2x^{2}+8x+9x-45}{(x-5)(x+4)}=\frac{2x^{2}+17x-45}{(x-5)(x+4)}$