Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 690: 5


$-\frac{x+3}{x+4}, with$ $x\ne-4,x\ne3$

Work Step by Step

Given : $\frac{9-x^{2}}{x^{2}+x-12}=\frac{(3+x)(3-x)}{x^{2}+x-12}$ (Since $(a^{2}-b^{2})=(a+b)(a-b)$) This becomes : $\frac{(3+x)(3-x)}{(x+4)(x-3)}=-\frac{x+3}{x+4}$
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