Answer
$\frac{1}{7(d+1)}$
Work Step by Step
Given : $\frac{4d^{2}-3d}{7d} \times \frac{1}{4d^{2}+d-3}=\frac{4d^{2}-3d}{7d(4d^{2}+d-3)}=\frac{4d-3}{7(4d-3)(d+1)}=\frac{1}{7(d+1)}$
(After dividing out the common factors $d$ and $(4d-3)$)
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 690: 12
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