Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 690: 21



Work Step by Step

Given : $\frac{p}{x^{2}+x-12} = \frac{x+5}{x-3}$ Thus, $p=\frac{(x+5)(x^{2}+x-12)}{(x-3)}= \frac{(x+5)(x+4)(x-3)}{(x-3)}=(x+5)(x+4)$ $=x^{2}+9x+20$ (After dividing out the common factor (x-3))
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