Answer
The solution is $x=1$.
Work Step by Step
$\sqrt 2-x=x$
Square both sides:
$2-x=x^2$
$x^2+x-2=0$
$x-1=0$ or $x+2=0$
$x=1$ or $x=-2$
Check:
$\sqrt 2-1=x$
$1=\sqrt 1$
$\sqrt 2-(-2)=-2$
$2=-2$
The solution is $x=1$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 20
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