## Algebra 1: Common Core (15th Edition)

$\frac{2\sqrt 6+3}{5}$
We are given: $\frac{\sqrt 6}{4-\sqrt 6}$ Multiplying the equation with $\frac{4+\sqrt 6}{4+\sqrt 6}$ $=\frac{\sqrt 6(4+\sqrt 6)}{16-6}$ $=\frac{4\sqrt 6+6}{10}$ $=\frac{2\sqrt 6+3}{5}$