Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 14



Work Step by Step

We are given: $\frac{\sqrt 2}{\sqrt 2+3}$ Multiplying the equation with $\frac{\sqrt2-3}{\sqrt2-3}$ $=\frac{\sqrt 2(\sqrt2-3)}{2-9}$ $=\frac{2-3\sqrt 2}{-7}$ $=\frac{1}{7}(3\sqrt2-2)$
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