Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 11

Answer

$-\frac{\sqrt 6}{2}$

Work Step by Step

We are given: $-\frac{\sqrt 18}{\sqrt 12}$ $=-\frac{\sqrt 3.\sqrt 6}{\sqrt 4.3}$ $=-\frac{\sqrt 3.\sqrt 6}{2\sqrt 3}$ $=-\frac{\sqrt 6}{2}$
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