Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 16


The solution is $x=\frac{9}{2}$.

Work Step by Step

$\sqrt 2x+4=7$ $\sqrt 2x=3$ Square both sides: $2x=9$ $x=\frac{9}{2}$ Check: $\sqrt 2(\frac{9}{2})+4=7$ $7=7$ The solution is $x=\frac{9}{2}$.
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