Answer
$k=1296$
Work Step by Step
You are given $\sqrt {k}-8=28$. Solve for k:
$\sqrt k-8=28$
$\sqrt {(k)^2} = {36}^{2}$
$k=1296$
Check solution:
$\sqrt {1296}-8=28$
$36-8=28$
$28=28$
The solution is $k=1296$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 17
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