## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 17

#### Answer

$k=1296$

#### Work Step by Step

You are given $\sqrt {k}-8=28$. Solve for k: $\sqrt k-8=28$ $\sqrt {(k)^2} = {36}^{2}$ $k=1296$ Check solution: $\sqrt {1296}-8=28$ $36-8=28$ $28=28$ The solution is $k=1296$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.