Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Test - Page 657: 12


$\frac{1}{13}(4-\sqrt 3)$

Work Step by Step

We are given: $\frac{1}{\sqrt3+4}$ Multiplying with $\frac{\sqrt 3-4}{\sqrt 3-4}$ $=\frac{\sqrt 3-4}{3-16}$ $=\frac{\sqrt 3-4}{-13}$ $=\frac{1}{13}(4-\sqrt 3)$
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