Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 44


The solution is $x=\frac{1}{2}$.

Work Step by Step

$2x=\sqrt 2-2x$ Square both sides: $4x^2=2-2x$ $4x^2+2x-2=0$ $(2x-1)(x+1)=0$ $2x-1=0$ or $x+1=0$ $x=\frac{1}{2}$ or $x=-1$ Check: $2(\frac{1}{2})=\sqrt 2-2(\frac{1}{2})$ $1=1$ $2(-1)=\sqrt 2-2(-1)$ $-2=2$ The solution is $x=\frac{1}{2}$.
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