Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 38



Work Step by Step

You are given $4+\sqrt y=7$.Solve for y: $\sqrt y=3$ $\sqrt {(y)^2} = {3}^{2}$ -square both sides- $y=9$ Check solution: $4+\sqrt {9}=7$ $4+3=7$ $7=7$ The solution is $y=9$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.