Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 41


The solution is $d=2$.

Work Step by Step

$\sqrt 2+d=d$ Square both sides: $2+d=d^2$ $d^2-d-2=0$ $(d-2)(d+1)=0$ $d-2=0$ or $d+1=0$ $d=2$ or $d=-1$ Check: $\sqrt 2+2=2$ $2=2$ $\sqrt 2+(-1)=-1$ $1 \ne -1$ The solution is $d=2$.
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