## Algebra 1: Common Core (15th Edition)

$-\frac{3\sqrt 2+9}{7}$
Applying the rules of radicals: $\frac{3}{\sqrt 2-3}$ Multiply each side with $\frac{\sqrt 2+3}{\sqrt 2+3}$ $=\frac{3(\sqrt 2+3)}{2-9}$ $=-\frac{3\sqrt 2+9}{7}$