Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 37



Work Step by Step

You are given $\sqrt x-5=8$.Solve for X: $\sqrt x=13$ $\sqrt {(x)^2} = {13}^{2}$ -square both sides- $x=169$ Check solution: $\sqrt {169} -5=8$ $13-5=8$ $8=8$ The solution is $x=169$
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