Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 35


$=-2+\sqrt 3$

Work Step by Step

Applying the rules of radicals: $\frac{\sqrt 3-3}{\sqrt 3+3}$ Multiply each side with $\frac{\sqrt 3-3}{\sqrt 3-3}$ $=\frac{(\sqrt 3-3)^2}{3-9}$ $=\frac{3 -6\sqrt 3+9}{-6}$ $=-2+\sqrt 3$
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