Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 655: 39



Work Step by Step

You are given $\sqrt {w-2}=4$. Solve for w: $\sqrt {w-2}=4$ $\sqrt {(w-2)^2} = {4}^{2}$ $w-2=16$ $w=18$ Check solution: $\sqrt {18-2}=4$ $\sqrt {16}=4$ $4=4$ The solution is $w=18$.
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