Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 23



Work Step by Step

You are given $\sqrt (n+5)$=$\sqrt (5n-11)$.Solve for N: $\sqrt (n+5)$=$\sqrt (5n-11)$ -square both sides- $\sqrt (n+5$$)^{2}$=$\sqrt (5n-11$$)^{2}$ n+5=5n-11 -4n+5=-11 -4n=-16 4=n The final solution is n=4.
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