Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 22



Work Step by Step

You are given $\sqrt (s+10)$=$\sqrt (6-s)$.Solve for S: $\sqrt (s+10)$=$\sqrt (6-s)$ -square both sides- ($\sqrt (s+10$$)^{2}$=($\sqrt (6-s$$)^{2}$ s+10=6-s 2s+10=6 2s=-4 s=-2 The final solution is s=-2
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