## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 20

y=3

#### Work Step by Step

You are given $\sqrt 2y$=$\sqrt (9-y)$.Solve for y: $\sqrt 2y$=$\sqrt (9-y)$ -square both sides- 2y=9-y 3y=9 y=3 The final solution is y=3

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