Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 14



Work Step by Step

You are given $\sqrt (10b+6)$=6.Solve for B: $\sqrt (10b+6)$=6 -square both sides- 10b+6=36 10b=30 b=3 The final solution is b=3
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