## Algebra 1: Common Core (15th Edition)

$x=\frac{9}{2}$
We are given: $\sqrt 3x+1=\sqrt 5x-8$ Square each side: $(\sqrt 3x+1)^2=(\sqrt 5x-8)^2$ $3x+1=5x-8$ $2x=9$ $x=\frac{9}{2}$ Check: $\sqrt 3(\frac{9}{2})+1=\sqrt 5(\frac{9}{2})-8$ $\frac{\sqrt 58}{2}=\frac{\sqrt 58}{2}$ Therefore, the solution is $x=\frac{9}{2}$