Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 11



Work Step by Step

You are given $\sqrt 2b$+4=8.Solve for b: $\sqrt 2b$+4=8 -subtract 4 from both sides- $\sqrt 2b$=4 -square both sides- ($\sqrt 2b$$)^{2}$=$4^{2}$ 2b=16 -divide both sides by 2- b=8 b=8
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