Answer
8
Work Step by Step
You are given $\sqrt 2b$+4=8.Solve for b:
$\sqrt 2b$+4=8 -subtract 4 from both sides-
$\sqrt 2b$=4 -square both sides-
($\sqrt 2b$$)^{2}$=$4^{2}$
2b=16 -divide both sides by 2-
b=8
b=8
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 11
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