Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 636: 10



Work Step by Step

You are given $\sqrt n$-3=6.Solve for n: $\sqrt n$-3=6 -add 3 to both sides- $\sqrt n$=9 -square both sides- ($\sqrt n$$)^{2}$=$9^{2}$ n=81
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