Answer
There is a total of 24 $ moles $ of $H$ in 1.0 mole of $C_{20}H_{24}N_2O_2$
Work Step by Step
1. Identify the conversion factor for $C_{20}H_{24}N_2O_2$ moles and $H$ moles.
- Each $C_{20}H_{24}N_2O_2$ molecule has 24 hydrogen atoms (H). Therefore:
$\frac{1mole(C_{20}H_{24}N_2O_2)}{24moles(H)}$ and $\frac{24moles(H)}{1mole(C_{20}H_{24}N_2O_2)}$
2. Calculate the amount of $H$ (in moles), in $1.0$ moles of $C_{20}H_{24}N_2O_2$:
$1.0 moles(C_{20}H_{24}N_2O_2) \times \frac{24moles(H)}{1mole(C_{20}H_{24}N_2O_2)} = 24 $ moles $ (H)$
