Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.1 - The Mole - Questions and Problems - Page 216: 7.3d

Answer

There are 14.1 moles of $C_2H_6O$ in $8.50 \times 10^{24}$ molecules of that.

Work Step by Step

1. State the data and objective: $8.50 \times 10^{24}$ molecules of $C_2H_6O$ Objective: Number of $C_2H_6O$ moles. 2. Identify the conversion factor. Using Avogadro's number: 1 mole $(X)$ $= 6.02 \times 10^{23}$ $(X)$ $molecules$ $\frac{1 mole (X)}{6.02 \times 10^{23} molecules (X)}$ and $\frac{6.02 \times 10^{23} molecules (X)}{1 mole (X)}$ 3. Use the conversion factor and the data to calculate the number of $C_2H_6O$ moles: $8.50 \times 10^{24} molecules (C_2H_6O) \times \frac{1 mole (C_2H_6O)}{6.02 \times 10^{23} molecules (C_2H_6O)} = 14.1moles(C_2H_6O)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.