Answer
There is a total of $9.0$ moles of $S$ atoms in $3.0$ moles of $Al_2(SO_4)_3$.
Work Step by Step
1. Identify the conversion factor for $Al_2(SO_4)_3$ moles and $S$ moles.
- Each $Al_2(SO_4)_3$ molecule has 3 sulfur atoms (S). Therefore:
$\frac{1mole(Al_2(SO_4)_3)}{3moles(S)}$ and $\frac{3moles(S)}{1mole(Al_2(SO_4)_3)}$
2. Calculate the amount of $S$ (in moles), in $3.0$ moles of $Al_2(SO_4)_3$:
$3.0 moles(Al_2(SO_4)_3) \times \frac{3moles(S)}{1mole(Al_2(SO_4)_3)} = 9.0 $ moles $ (S)$
