Answer
There is 0.623 mole of $C_2H_6$ in $3.75 \times 10^{23}$ molecules of that.
Work Step by Step
1. State the data and objective:
$3.75 \times 10^{23}$ molecules of $C_2H_6$
Objective: Number of $C_2H_6$ moles.
2. Identify the conversion factor.
Using Avogadro's number:
1 mole $(X)$ $= 6.02 \times 10^{23}$ $(X)$ $molecules$
$\frac{1 mole (X)}{6.02 \times 10^{23} molecules (X)}$ and $\frac{6.02 \times 10^{23} molecules (X)}{1 mole (X)}$
3. Use the conversion factor and the data to calculate the number of $C_2H_6$ moles:
$3.75 \times 10^{23} molecules (C_2H_6) \times \frac{1 mole (C_2H_6)}{6.02 \times 10^{23} molecules (C_2H_6)} = 0.623mole(C_2H_6)$
