Answer
There is a total of $1.0 \times 10^2$ moles of $C$ in 5.0 moles of $C_{20}H_{24}N_2O_2$.
Work Step by Step
1. Identify the conversion factor for $C_{20}H_{24}N_2O_2$ moles and $C$ moles.
- Each $C_{20}H_{24}N_2O_2$ molecule has 20 carbon atoms (C). Therefore:
$\frac{1mole(C_{20}H_{24}N_2O_2)}{20moles(C)}$ and $\frac{20moles(C)}{1mole(C_{20}H_{24}N_2O_2)}$
2. Calculate the amount of $C$ (in moles), in $1.0$ moles of $C_{20}H_{24}N_2O_2$:
$5.0 moles(C_{20}H_{24}N_2O_2) \times \frac{20moles(C)}{1mole(C_{20}H_{24}N_2O_2)} = 1.0 \times 10^2 $ moles $ (C)$
