Answer
There is a total of 8.00 moles of $O$ in 2.00 moles of $H_3PO_4$.
Work Step by Step
1. Identify the conversion factor for $H_3PO_4$ moles and $O$ moles.
- Each $H_3PO_4$ molecule has 4 oxygen atoms (O). Therefore:
$\frac{1mole(H_3PO_4)}{4moles(O)}$ and $\frac{4moles(O)}{1mole(H_3PO_4)}$
2. Calculate the amount of $O$ (in moles), in $2.00$ moles of $H_3PO_4$:
$2.00 moles(H_3PO_4) \times \frac{4moles(O)}{1mole(H_3PO_4)} = 8.00 $ moles $ (O)$
