Answer
There is a total of $0.040$ mole of $N$ atoms in $0.020$ mole of $C_{20}H_{24}N_2O_2$.
Work Step by Step
1. Identify the conversion factor for $C_{20}H_{24}N_2O_2$ moles and $N$ moles.
- Each $C_{20}H_{24}N_2O_2$ molecule has 2 nitrogen atoms (N). Therefore:
$\frac{1mole(C_{20}H_{24}N_2O_2)}{2moles(N)}$ and $\frac{2moles(N)}{1mole(C_{20}H_{24}N_2O_2)}$
2. Calculate the amount of $N$ (in moles), in $0.020$ mole of $C_{20}H_{24}N_2O_2$:
$0.020 mole(C_{20}H_{24}N_2O_2) \times \frac{2moles(N)}{1mole(C_{20}H_{24}N_2O_2)} = 0.040 $ mole $ (N)$
