Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.1 - The Mole - Questions and Problems - Page 216: 7.8c

Answer

There is a total of 4.5 moles of $SO{_4}^{2-}$ in 1.5 mole of $Al_2(SO_4)_3$.

Work Step by Step

1. Identify the conversion factor for $Al_2(SO_4)_3$ moles and $SO{_4}^{2-}$ moles. - Each $Al_2(SO_4)_3$ molecule has 3 $SO{_4}^{2-}$. Therefore: $\frac{1mole(Al_2(SO_4)_3)}{3moles(SO{_4}^{2-})}$ and $\frac{3moles(SO{_4}^{2-})}{1mole(Al_2(SO_4)_3)}$ 2. Calculate the amount of $SO{_4}^{2-}$ (in moles), in $1.5$ moles of $Al_2(SO_4)_3$: $1.5 moles(Al_2(SO_4)_3) \times \frac{3moles(SO{_4}^{2-})}{1mole(Al_2(SO_4)_3)} = 4.5 $ moles $ (SO{_4}^{2-})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.