Answer
There is a total of 6.00 moles of $H$ in 2.00 moles of $H_3PO_4$
Work Step by Step
1. Identify the conversion factor for $H_3PO_4$ moles and $H$ moles.
- Each $H_3PO_4$ molecule has 3 hydrogens (H). Therefore:
$\frac{1mole(H_3PO_4)}{3moles(H)}$ and $\frac{3moles(H)}{1mole(H_3PO_4)}$
2. Calculate the amount of $H$ (in moles), in $2.00$ moles of $H_3PO_4$:
$2.00 moles(H_3PO_4) \times \frac{3moles(H)}{1mole(H_3PO_4)} = 6.00 $ moles $ (H)$
