Answer
There is a total of $1.20 \times 10^{24}$ atoms of $P$ in $2.00$ moles of $H_3PO_4$.
Work Step by Step
1. Identify the conversion factors for $H_3PO_4$ moles to $P$ atoms.
- Each $H_3PO_4$ molecule has 1 $P$ atom. Therefore:
$\frac{1mole(H_3PO_4)}{1mole(P)}$ and $\frac{1mole(P)}{1mole(H_3PO_4)}$
- Using Avogadro's number:
1 mole $(X)$ $= 6.02 \times 10^{23}$ $(X)$ $atoms$
$\frac{1 mole (X)}{6.02 \times 10^{23} atoms (X)}$ and $\frac{6.02 \times 10^{23} atoms (X)}{1 mole (X)}$
2. Calculate the amount of $P$ atoms in $2.00$ moles of $H_3PO_4$:
$2.00 moles(H_3PO_4) \times \frac{1mole(P)}{1mole(H_3PO_4)} \times \frac{6.02 \times 10^{23} atoms (P)}{1 mole (P)}= 1.20 \times 10^{24} $ atoms $ (P)$
