Answer
$\frac{\sqrt 3}{2}$
Work Step by Step
We know, $\sin \frac{\pi}{6}=\frac{1}{2}$
$\implies \sin^{-1}\frac{1}{2}=\frac{\pi}{6}$
Then, $\cos(\sin^{-1}\frac{1}{2})=\cos(\frac{\pi}{6})=\frac{\sqrt 3}{2}$
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