Answer
$\frac{3}{5}$
Work Step by Step
Recall that $\sin(\sin^{-1}x)=x$ if $x$ belongs to [-1,1].
Therefore, $\sin(\sin^{-1}\frac{3}{5})=\frac{3}{5}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 55
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