Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 56

Answer

$\dfrac{3}{5}$

Work Step by Step

Let us consider $\theta =\cos^{-1} (\dfrac{3}{5})$ This gives: $\cos \theta =\dfrac{3}{5}$ Now, $\cos [\cos^{-1} (\dfrac{3}{5})]=\dfrac{3}{5}$
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