Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 78

Answer

$ =\frac{4}{5}$

Work Step by Step

To find $\cos (\tan ^ {–1} \frac{3}{4})$ let, $\tan ^ {–1} \frac{3}{4} = \theta$ then, $\tan \theta = \frac{3}{4}$ We know, if $\tan \theta = \frac{p}{b}$, then $\cos \theta = \frac{b}{\sqrt{p^2 + b^2}}$ $\cos \theta = \frac{4}{\sqrt{3^2 + 4^2}}$ $ =\frac{4}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.