Answer
$\dfrac{1}{\sqrt 2}$
Work Step by Step
Let us consider $\theta =\sin^{-1} (\dfrac{1}{\sqrt 2})$
This gives: $\sin \theta =\dfrac{1}{\sqrt 2}$
Now,
$\sin [\sin^{-1} (\dfrac{1}{\sqrt 2})]=\dfrac{1}{\sqrt 2}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 58
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