Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 64

Answer

$\frac{\pi}{4}$

Work Step by Step

Within the restricted interval ($-\frac{\pi}{2}\leq\theta\leq\frac{\pi}{2}$), $\sin^{-1}(\sin\theta)=\theta$ Therefore, $\sin^{-1}(\sin\frac{\pi}{4})=\frac{\pi}{4}$
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