Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 67

Answer

$\frac{\pi}{4}$

Work Step by Step

$\frac{7\pi}{4}$ is coterminal with $(\frac{7\pi}{4}-2\pi)=-\frac{\pi}{4}$: $\cos\frac{7\pi}{4}=\cos(-\frac{\pi}{4})=\cos\frac{\pi}{4}$ Then, $\cos^{-1}(\cos \frac{7\pi}{4})=\cos^{-1}(\cos\frac{\pi}{4})$ Within the restricted interval ($0\leq\theta\leq\pi$), $\cos^{-1}(\cos\theta)=\theta$ Therefore, $\cos^{-1}(\cos \frac{\pi}{4})=\frac{\pi}{4}$
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