Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 77

Answer

$\frac{\sqrt 3}{2}$

Work Step by Step

We know, $\cos \frac{\pi}{3}=\frac{1}{2}$ $\implies \cos^{-1}\frac{1}{2}=\frac{\pi}{3}$ Then, $\sin(\cos^{-1}\frac{1}{2})=\sin(\frac{\pi}{3})=\frac{\sqrt 3}{2}$
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