Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 74

Answer

$=\frac{5}{3}$

Work Step by Step

$\csc (\tan ^ {–1} \frac{3}{4})$ let, $\tan ^ {–1} \frac{3}{4} = \theta$ then, $\tan \theta =\frac{3}{4}$ We know, $\csc \theta = \sqrt{1+ \cot ^2 \theta}$ $\csc \theta = \sqrt{1 +( \frac{4}{3})^2}$ $ =\frac{5}{3}$
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