Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - 4.7 Problem Set - Page 262: 85

Answer

$\sqrt{1 – x^2}$

Work Step by Step

let, $\sin ^ {–1} x = \theta$ then, $\sin \theta = x$ – –––(1) To evaluate $\cos (\sin ^ {–1} x) = \cos \theta$ We know, $\cos \theta = \sqrt{1 – \sin^{2} \theta}$ using(1) $\cos \theta = \sqrt{1 – x^2}$
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