Answer
$$-2$$
Work Step by Step
$x^{5}+32=0$
$x^{5}+32-32=0-32$
$x^{5}=-32$
$x^{5}=(-2)^{5}$
$(x^5)^{\frac{1}{5}}=((-2)^{5})^{\frac{1}{5}}$
$(x^5)^{\frac{1}{5}}=(-2)^{5}{^\frac{1}{5}}$
$x=-2$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 113
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