Answer
$\frac{0.2}{\sqrt[3] x^{2}}+\frac{3\sqrt x}{7}$
Work Step by Step
$0.2x^{-\frac{2}{3}}+\frac{3}{7x^{-\frac{1}{2}}}=\frac{0.2}{x^{\frac{2}{3}}}+\frac{3}{\frac{7}{x^{\frac{1}{2}}}}=\frac{0.2}{x^{\frac{2}{3}}}+\frac{3x^{\frac{1}{2}}}{7}=\frac{0.2}{\sqrt[3] x^{2}}+\frac{3\sqrt x}{7}$
