Answer
$$ \frac{2}{3}$$
$$and$$
$$ -\frac{2}{3}$$
Work Step by Step
$x^{2}-\frac{4}{9}=0$
$x^{2}-\frac{4}{9}+\frac{4}{9}=0+\frac{4}{9}$
$x^{2}=\frac{4}{9}$
$x=+/-\sqrt \frac{4}{9}$
$x=+/-\frac{\sqrt 4}{\sqrt 9}$
$x=+/-\frac{2}{3}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 109
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