Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 110

Answer

$$\frac{1}{\sqrt 10}$$ $$and$$ $$-\frac{1}{\sqrt 10}$$

Work Step by Step

$x^{2}-\frac{1}{10}=0$ $x^{2}-\frac{1}{10}+\frac{1}{10}=0+\frac{1}{10}$ $x^{2}=\frac{1}{10}$ $x=+/-\sqrt \frac{1}{10}$ $x=+/-\frac{\sqrt 1}{\sqrt 10}$ $x=+/-\frac{1}{\sqrt 10}$
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