Answer
$$4$$ $$and$$ $$-4$$
Work Step by Step
$x^{2}-16+0$
$x^{2}-16+16=0+16$
$x^{2}+16$
$x=\pm \sqrt 16$
$x=\pm(4)$
Thus the answer is +4 and -4
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 107
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
